Method 1
String[] arr = { "ab", "bcd", "cdef", "defgh", "efhik", "fghijk", "ghijkl" }; Stream<String> stream = Stream.of(arr); |
Method 2
String[] arr = { "ab", "bcd", "cdef", "defgh", "efhik", "fghijk", "ghijkl" }; Stream<String> stream = Stream.of(arr); ArrayList<String> list = stream.filter(x -> x.length() < 5).collect(Collectors.toCollection(ArrayList::new)); |
Method 3
String[] arr = { "ab", "bcd", "cdef", "defgh", "efhik", "fghijk", "ghijkl" }; Stream<String> stream = Stream.of(arr).parallel(); ArrayList<String> list = new ArrayList<String>(); stream.forEach(list::add); |
Method 4
If a stream is paralleled, the forEachOrdered() method should be used instead of forEach().
String[] arr = { "ab", "bcd", "cdef", "defgh", "efhik", "fghijk", "ghijkl" }; Stream<String> stream = Stream.of(arr).parallel(); ArrayList<String> list = new ArrayList<String>(); stream.forEachOrdered(list::add); |