Python django.conf.settings.IGNORABLE_404_URLS Examples

The following are 7 code examples of django.conf.settings.IGNORABLE_404_URLS(). You can vote up the ones you like or vote down the ones you don't like, and go to the original project or source file by following the links above each example. You may also want to check out all available functions/classes of the module django.conf.settings , or try the search function .
Example #1
Source File: common.py    From luscan-devel with GNU General Public License v2.0 6 votes vote down vote up 
def _is_ignorable_404(uri):
    """
    Returns True if a 404 at the given URL *shouldn't* notify the site managers.
    """
    if getattr(settings, 'IGNORABLE_404_STARTS', ()):
        import warnings
        warnings.warn('The IGNORABLE_404_STARTS setting has been deprecated '
                      'in favor of IGNORABLE_404_URLS.', DeprecationWarning)
        for start in settings.IGNORABLE_404_STARTS:
            if uri.startswith(start):
                return True
    if getattr(settings, 'IGNORABLE_404_ENDS', ()):
        import warnings
        warnings.warn('The IGNORABLE_404_ENDS setting has been deprecated '
                      'in favor of IGNORABLE_404_URLS.', DeprecationWarning)
        for end in settings.IGNORABLE_404_ENDS:
            if uri.endswith(end):
                return True
    return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #2
Source File: common.py    From openhgsenti with Apache License 2.0 6 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Return True if the given request *shouldn't* notify the site managers
        according to project settings or in three specific situations:
         - If the referer is empty.
         - If a '?' in referer is identified as a search engine source.
         - If the referer is equal to the current URL, ignoring the scheme
           (assumed to be a poorly implemented bot).
        """
        if not referer:
            return True

        if not self.is_internal_request(domain, referer) and '?' in referer:
            return True

        parsed_referer = urlparse(referer)
        if parsed_referer.netloc in ['', domain] and parsed_referer.path == uri:
            return True

        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #3
Source File: common.py    From GTDWeb with GNU General Public License v2.0 5 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Returns True if the given request *shouldn't* notify the site managers.
        """
        # '?' in referer is identified as search engine source
        if (not referer or
                (not self.is_internal_request(domain, referer) and '?' in referer)):
            return True
        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #4
Source File: common.py    From bioforum with MIT License 5 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Return True if the given request *shouldn't* notify the site managers
        according to project settings or in situations outlined by the inline
        comments.
        """
        # The referer is empty.
        if not referer:
            return True

        # APPEND_SLASH is enabled and the referer is equal to the current URL
        # without a trailing slash indicating an internal redirect.
        if settings.APPEND_SLASH and uri.endswith('/') and referer == uri[:-1]:
            return True

        # A '?' in referer is identified as a search engine source.
        if not self.is_internal_request(domain, referer) and '?' in referer:
            return True

        # The referer is equal to the current URL, ignoring the scheme (assumed
        # to be a poorly implemented bot).
        parsed_referer = urlparse(referer)
        if parsed_referer.netloc in ['', domain] and parsed_referer.path == uri:
            return True

        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #5
Source File: common.py    From Hands-On-Application-Development-with-PyCharm with MIT License 5 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Return True if the given request *shouldn't* notify the site managers
        according to project settings or in situations outlined by the inline
        comments.
        """
        # The referer is empty.
        if not referer:
            return True

        # APPEND_SLASH is enabled and the referer is equal to the current URL
        # without a trailing slash indicating an internal redirect.
        if settings.APPEND_SLASH and uri.endswith('/') and referer == uri[:-1]:
            return True

        # A '?' in referer is identified as a search engine source.
        if not self.is_internal_request(domain, referer) and '?' in referer:
            return True

        # The referer is equal to the current URL, ignoring the scheme (assumed
        # to be a poorly implemented bot).
        parsed_referer = urlparse(referer)
        if parsed_referer.netloc in ['', domain] and parsed_referer.path == uri:
            return True

        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #6
Source File: common.py    From python with Apache License 2.0 5 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Return True if the given request *shouldn't* notify the site managers
        according to project settings or in situations outlined by the inline
        comments.
        """
        # The referer is empty.
        if not referer:
            return True

        # APPEND_SLASH is enabled and the referer is equal to the current URL
        # without a trailing slash indicating an internal redirect.
        if settings.APPEND_SLASH and uri.endswith('/') and referer == uri[:-1]:
            return True

        # A '?' in referer is identified as a search engine source.
        if not self.is_internal_request(domain, referer) and '?' in referer:
            return True

        # The referer is equal to the current URL, ignoring the scheme (assumed
        # to be a poorly implemented bot).
        parsed_referer = urlparse(referer)
        if parsed_referer.netloc in ['', domain] and parsed_referer.path == uri:
            return True

        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)
Example #7
Source File: common.py    From python2017 with MIT License 5 votes vote down vote up 
def is_ignorable_request(self, request, uri, domain, referer):
        """
        Return True if the given request *shouldn't* notify the site managers
        according to project settings or in situations outlined by the inline
        comments.
        """
        # The referer is empty.
        if not referer:
            return True

        # APPEND_SLASH is enabled and the referer is equal to the current URL
        # without a trailing slash indicating an internal redirect.
        if settings.APPEND_SLASH and uri.endswith('/') and referer == uri[:-1]:
            return True

        # A '?' in referer is identified as a search engine source.
        if not self.is_internal_request(domain, referer) and '?' in referer:
            return True

        # The referer is equal to the current URL, ignoring the scheme (assumed
        # to be a poorly implemented bot).
        parsed_referer = urlparse(referer)
        if parsed_referer.netloc in ['', domain] and parsed_referer.path == uri:
            return True

        return any(pattern.search(uri) for pattern in settings.IGNORABLE_404_URLS)