Python __builtin__.compile() Examples

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
    return rv 

def compile(source, filename, *args):
    try:
        return _compile(source, filename, *args)
    except SyntaxError:
        ver = sys.version_info

        if ver[0] > 2 and ver[1] > 4:
            raise
        if 'import asyncio' in source or 'from asyncio' in source:
            return _compile('', filename, *args)
        raise 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
    return rv 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def main(args=None):
    """Compile several source files.

    The files named in 'args' (or on the command line, if 'args' is
    not specified) are compiled and the resulting bytecode is cached
    in the normal manner.  This function does not search a directory
    structure to locate source files; it only compiles files named
    explicitly.  If '-' is the only parameter in args, the list of
    files is taken from standard input.

    """
    if args is None:
        args = sys.argv[1:]
    rv = 0
    if args == ['-']:
        while True:
            filename = sys.stdin.readline()
            if not filename:
                break
            filename = filename.rstrip('\n')
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                rv = 1
                sys.stderr.write("%s\n" % error.msg)
            except IOError as error:
                rv = 1
                sys.stderr.write("%s\n" % error)
    else:
        for filename in args:
            try:
                compile(filename, doraise=True)
            except PyCompileError as error:
                # return value to indicate at least one failure
                rv = 1
                sys.stderr.write(error.msg)
    return rv 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def _compile(pathname, timestamp):
    """Compile (and cache) a Python source file.

    The file specified by <pathname> is compiled to a code object and
    returned.

    Presuming the appropriate privileges exist, the bytecodes will be
    saved back to the filesystem for future imports. The source file's
    modification timestamp must be provided as a Long value.
    """
    codestring = open(pathname, 'rU').read()
    if codestring and codestring[-1] != '\n':
        codestring = codestring + '\n'
    code = __builtin__.compile(codestring, pathname, 'exec')

    # try to cache the compiled code
    try:
        f = open(pathname + _suffix_char, 'wb')
    except IOError:
        pass
    else:
        f.write('\0\0\0\0')
        f.write(struct.pack('<I', timestamp))
        marshal.dump(code, f)
        f.flush()
        f.seek(0, 0)
        f.write(imp.get_magic())
        f.close()

    return code 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__, err, dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__, err, dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__, err, dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__,err.args,dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__,err.args,dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__, err, dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__, err, dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__,err.args,dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return 

def compile(file, cfile=None, dfile=None, doraise=False):
    """Byte-compile one Python source file to Python bytecode.

    Arguments:

    file:    source filename
    cfile:   target filename; defaults to source with 'c' or 'o' appended
             ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo)
    dfile:   purported filename; defaults to source (this is the filename
             that will show up in error messages)
    doraise: flag indicating whether or not an exception should be
             raised when a compile error is found. If an exception
             occurs and this flag is set to False, a string
             indicating the nature of the exception will be printed,
             and the function will return to the caller. If an
             exception occurs and this flag is set to True, a
             PyCompileError exception will be raised.

    Note that it isn't necessary to byte-compile Python modules for
    execution efficiency -- Python itself byte-compiles a module when
    it is loaded, and if it can, writes out the bytecode to the
    corresponding .pyc (or .pyo) file.

    However, if a Python installation is shared between users, it is a
    good idea to byte-compile all modules upon installation, since
    other users may not be able to write in the source directories,
    and thus they won't be able to write the .pyc/.pyo file, and then
    they would be byte-compiling every module each time it is loaded.
    This can slow down program start-up considerably.

    See compileall.py for a script/module that uses this module to
    byte-compile all installed files (or all files in selected
    directories).

    """
    with open(file, 'U') as f:
        try:
            timestamp = long(os.fstat(f.fileno()).st_mtime)
        except AttributeError:
            timestamp = long(os.stat(file).st_mtime)
        codestring = f.read()
    try:
        codeobject = __builtin__.compile(codestring, dfile or file,'exec')
    except Exception,err:
        py_exc = PyCompileError(err.__class__,err.args,dfile or file)
        if doraise:
            raise py_exc
        else:
            sys.stderr.write(py_exc.msg + '\n')
            return