Java Code Examples for org.apache.directory.api.ldap.model.name.Dn#getRdns()
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org.apache.directory.api.ldap.model.name.Dn#getRdns() .
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Example 1
Source File: DnNode.java From directory-ldap-api with Apache License 2.0 | 5 votes |
/** * Tells if there is a parent for a given Dn,. This parent should be a * subset of the given dn.<br> * For instance, if we have stored dc=acme, dc=org into the tree, * the Dn: ou=example, dc=acme, dc=org will have a parent * <br>For the Dn ou=apache, dc=org, there is no parent, so false will be returned. * * @param dn the normalized distinguished name to resolve to a parent * @return true if there is a parent associated with the normalized dn */ public synchronized boolean hasParent( Dn dn ) { List<Rdn> rdns = dn.getRdns(); DnNode<N> currentNode = this; DnNode<N> parentNode = null; // Iterate through all the Rdn until we find the associated element for ( int i = rdns.size() - 1; i >= 0; i-- ) { Rdn rdn = rdns.get( i ); if ( rdn.equals( currentNode.nodeRdn ) ) { parentNode = currentNode; } else if ( currentNode.hasChildren() ) { currentNode = currentNode.children.get( rdn.getNormName() ); if ( currentNode == null ) { break; } parentNode = currentNode; } else { break; } } return parentNode != null; }
Example 2
Source File: DnNode.java From directory-ldap-api with Apache License 2.0 | 5 votes |
/** * Removes a node from the tree. * * @param dn the node's Dn * @throws LdapException if the Dn is null or empty */ public synchronized void remove( Dn dn ) throws LdapException { checkDn( dn ); // Find the parent first : we won't be able to remove // a node if it's not present in the tree ! DnNode<N> parentNode = getNode( dn ); if ( parentNode == null ) { return; } // Now, check that this parent has the same Dn than the one // we gave and that there is no children if ( ( dn.size() != parentNode.depth ) || parentNode.hasChildren() ) { return; } // Ok, no children, same Dn, let's remove what we can. parentNode = parentNode.getParent(); for ( Rdn rdn : dn.getRdns() ) { parentNode.children.remove( rdn.getNormName() ); if ( parentNode.children.size() > 0 ) { // We have to stop here, because the parent's node is shared with other Node. break; } parentNode = parentNode.getParent(); } }
Example 3
Source File: DnNode.java From directory-ldap-api with Apache License 2.0 | 5 votes |
/** * Get the closest Node for a given Dn which has an element, if present in the tree.<br> * For instance, if we have stored dc=acme, dc=org into the tree, * the Dn: ou=example, dc=acme, dc=org will have a parent, and * dc=acme, dc=org will be returned if it has an associated element. * <br>For the Dn ou=apache, dc=org, there is no parent, so null will be returned. * * @param dn the normalized distinguished name to resolve to a parent * @return the Node associated with the normalized dn */ public synchronized boolean hasParentElement( Dn dn ) { List<Rdn> rdns = dn.getRdns(); DnNode<N> currentNode = this; boolean hasElement = false; // Iterate through all the Rdn until we find the associated partition for ( int i = rdns.size() - 1; i >= 0; i-- ) { Rdn rdn = rdns.get( i ); if ( currentNode.hasChildren() ) { currentNode = currentNode.children.get( rdn.getNormName() ); if ( currentNode == null ) { break; } if ( currentNode.hasElement() ) { hasElement = true; } parent = currentNode; } else { break; } } return hasElement; }
Example 4
Source File: DnNode.java From directory-ldap-api with Apache License 2.0 | 5 votes |
/** * Get the closest Node for a given Dn which has an element, if present in the tree.<br> * For instance, if we have stored dc=acme, dc=org into the tree, * the Dn: ou=example, dc=acme, dc=org will have a parent, and * dc=acme, dc=org will be returned if it has an associated element. * <br>For the Dn ou=apache, dc=org, there is no parent, so null will be returned. * * @param dn the normalized distinguished name to resolve to a parent * @return the Node associated with the normalized dn */ public synchronized DnNode<N> getParentWithElement( Dn dn ) { List<Rdn> rdns = dn.getRdns(); DnNode<N> currentNode = this; DnNode<N> element = null; // Iterate through all the Rdn until we find the associated partition for ( int i = rdns.size() - 1; i >= 1; i-- ) { Rdn rdn = rdns.get( i ); if ( currentNode.hasChildren() ) { currentNode = currentNode.children.get( rdn.getNormName() ); if ( currentNode == null ) { break; } if ( currentNode.hasElement() ) { element = currentNode; } parent = currentNode; } else { break; } } return element; }
Example 5
Source File: AuditMgrConsole.java From directory-fortress-core with Apache License 2.0 | 5 votes |
/** * Break the authZ eqDn attribute into 1. permission object name, 2. op name and 3. object id (optional). * * @param authZ contains the raw dn format from openldap slapo access log data * @return Permisison containing objName, opName and optionally the objId populated from the raw data. */ public static Permission getAuthZPerm(AuthZ authZ) throws LdapInvalidDnException { // This will be returned to the caller: Permission pOp = new Permission(); // Break dn into rdns for leaf and parent. Use the 'type' field in rdn. // The objId value is optional. If present it will be part of the parent's relative distinguished name.. // Here the sample reqDN=ftOpNm=TOP2_2+ftObjId=002,ftObjNm=TOB2_1,ou=Permissions,ou=RBAC,dc=example,dc=com // Will be mapped to objName=TOB2_1, opName=TOP2_2, objId=002, in the returned permission object. Dn dn = new Dn( authZ.getReqDN() ); if( dn.getRdns() != null && CollectionUtils.isNotEmpty( dn.getRdns() ) ) { for( Rdn rdn : dn.getRdns() ) { // The rdn type attribute will be mapped to objName, opName and objId fields. switch ( rdn.getType() ) { case GlobalIds.POP_NAME: pOp.setOpName( rdn.getType() ); break; case GlobalIds.POBJ_NAME: pOp.setObjName( rdn.getType() ); break; case GlobalIds.POBJ_ID: pOp.setObjId( rdn.getType() ); break; } } } return pOp; }