Java Code Examples for com.android.dx.rop.type.Type#isReference()
The following examples show how to use
com.android.dx.rop.type.Type#isReference() .
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Example 1
Source File: Simulator.java From Box with Apache License 2.0 | 4 votes |
/** * Returns the required array type for an array load or store * instruction, based on a given implied type and an observed * actual array type. * * <p>The interesting cases here have to do with object arrays, * <code>byte[]</code>s, <code>boolean[]</code>s, and * known-nulls.</p> * * <p>In the case of arrays of objects, we want to narrow the type * to the actual array present on the stack, as long as what is * present is an object type. Similarly, due to a quirk of the * original bytecode representation, the instructions for dealing * with <code>byte[]</code> and <code>boolean[]</code> are * undifferentiated, and we aim here to return whichever one was * actually present on the stack.</p> * * <p>In the case where there is a known-null on the stack where * an array is expected, our behavior depends on the implied type * of the instruction. When the implied type is a reference, we * don't attempt to infer anything, as we don't know the dimension * of the null constant and thus any explicit inferred type could * be wrong. When the implied type is a primitive, we fall back to * the implied type of the instruction. Due to the quirk described * above, this means that source code that uses * <code>boolean[]</code> might get translated surprisingly -- but * correctly -- into an instruction that specifies a * <code>byte[]</code>. It will be correct, because should the * code actually execute, it will necessarily throw a * <code>NullPointerException</code>, and it won't matter what * opcode variant is used to achieve that result.</p> * * @param impliedType {@code non-null;} type implied by the * instruction; is <i>not</i> an array type * @param foundArrayType {@code non-null;} type found on the * stack; is either an array type or a known-null * @return {@code non-null;} the array type that should be * required in this context */ private static Type requiredArrayTypeFor(Type impliedType, Type foundArrayType) { if (foundArrayType == Type.KNOWN_NULL) { return impliedType.isReference() ? Type.KNOWN_NULL : impliedType.getArrayType(); } if ((impliedType == Type.OBJECT) && foundArrayType.isArray() && foundArrayType.getComponentType().isReference()) { return foundArrayType; } if ((impliedType == Type.BYTE) && (foundArrayType == Type.BOOLEAN_ARRAY)) { /* * Per above, an instruction with implied byte[] is also * allowed to be used on boolean[]. */ return Type.BOOLEAN_ARRAY; } return impliedType.getArrayType(); }
Example 2
Source File: Merger.java From Box with Apache License 2.0 | 4 votes |
/** * Merges two frame types. * * @param ft1 {@code non-null;} a frame type * @param ft2 {@code non-null;} another frame type * @return {@code non-null;} the result of merging the two types */ public static TypeBearer mergeType(TypeBearer ft1, TypeBearer ft2) { if ((ft1 == null) || ft1.equals(ft2)) { return ft1; } else if (ft2 == null) { return null; } else { Type type1 = ft1.getType(); Type type2 = ft2.getType(); if (type1 == type2) { return type1; } else if (type1.isReference() && type2.isReference()) { if (type1 == Type.KNOWN_NULL) { /* * A known-null merges with any other reference type to * be that reference type. */ return type2; } else if (type2 == Type.KNOWN_NULL) { /* * The same as above, but this time it's type2 that's * the known-null. */ return type1; } else if (type1.isArray() && type2.isArray()) { TypeBearer componentUnion = mergeType(type1.getComponentType(), type2.getComponentType()); if (componentUnion == null) { /* * At least one of the types is a primitive type, * so the merged result is just Object. */ return Type.OBJECT; } return ((Type) componentUnion).getArrayType(); } else { /* * All other unequal reference types get merged to be * Object in this phase. This is fine here, but it * won't be the right thing to do in the verifier. */ return Type.OBJECT; } } else if (type1.isIntlike() && type2.isIntlike()) { /* * Merging two non-identical int-like types results in * the type int. */ return Type.INT; } else { return null; } } }
Example 3
Source File: Simulator.java From Box with Apache License 2.0 | 4 votes |
/** * Returns the required array type for an array load or store * instruction, based on a given implied type and an observed * actual array type. * * <p>The interesting cases here have to do with object arrays, * <code>byte[]</code>s, <code>boolean[]</code>s, and * known-nulls.</p> * * <p>In the case of arrays of objects, we want to narrow the type * to the actual array present on the stack, as long as what is * present is an object type. Similarly, due to a quirk of the * original bytecode representation, the instructions for dealing * with <code>byte[]</code> and <code>boolean[]</code> are * undifferentiated, and we aim here to return whichever one was * actually present on the stack.</p> * * <p>In the case where there is a known-null on the stack where * an array is expected, our behavior depends on the implied type * of the instruction. When the implied type is a reference, we * don't attempt to infer anything, as we don't know the dimension * of the null constant and thus any explicit inferred type could * be wrong. When the implied type is a primitive, we fall back to * the implied type of the instruction. Due to the quirk described * above, this means that source code that uses * <code>boolean[]</code> might get translated surprisingly -- but * correctly -- into an instruction that specifies a * <code>byte[]</code>. It will be correct, because should the * code actually execute, it will necessarily throw a * <code>NullPointerException</code>, and it won't matter what * opcode variant is used to achieve that result.</p> * * @param impliedType {@code non-null;} type implied by the * instruction; is <i>not</i> an array type * @param foundArrayType {@code non-null;} type found on the * stack; is either an array type or a known-null * @return {@code non-null;} the array type that should be * required in this context */ private static Type requiredArrayTypeFor(Type impliedType, Type foundArrayType) { if (foundArrayType == Type.KNOWN_NULL) { return impliedType.isReference() ? Type.KNOWN_NULL : impliedType.getArrayType(); } if ((impliedType == Type.OBJECT) && foundArrayType.isArray() && foundArrayType.getComponentType().isReference()) { return foundArrayType; } if ((impliedType == Type.BYTE) && (foundArrayType == Type.BOOLEAN_ARRAY)) { /* * Per above, an instruction with implied byte[] is also * allowed to be used on boolean[]. */ return Type.BOOLEAN_ARRAY; } return impliedType.getArrayType(); }
Example 4
Source File: Merger.java From Box with Apache License 2.0 | 4 votes |
/** * Merges two frame types. * * @param ft1 {@code non-null;} a frame type * @param ft2 {@code non-null;} another frame type * @return {@code non-null;} the result of merging the two types */ public static TypeBearer mergeType(TypeBearer ft1, TypeBearer ft2) { if ((ft1 == null) || ft1.equals(ft2)) { return ft1; } else if (ft2 == null) { return null; } else { Type type1 = ft1.getType(); Type type2 = ft2.getType(); if (type1 == type2) { return type1; } else if (type1.isReference() && type2.isReference()) { if (type1 == Type.KNOWN_NULL) { /* * A known-null merges with any other reference type to * be that reference type. */ return type2; } else if (type2 == Type.KNOWN_NULL) { /* * The same as above, but this time it's type2 that's * the known-null. */ return type1; } else if (type1.isArray() && type2.isArray()) { TypeBearer componentUnion = mergeType(type1.getComponentType(), type2.getComponentType()); if (componentUnion == null) { /* * At least one of the types is a primitive type, * so the merged result is just Object. */ return Type.OBJECT; } return ((Type) componentUnion).getArrayType(); } else { /* * All other unequal reference types get merged to be * Object in this phase. This is fine here, but it * won't be the right thing to do in the verifier. */ return Type.OBJECT; } } else if (type1.isIntlike() && type2.isIntlike()) { /* * Merging two non-identical int-like types results in * the type int. */ return Type.INT; } else { return null; } } }
Example 5
Source File: Simulator.java From J2ME-Loader with Apache License 2.0 | 4 votes |
/** * Returns the required array type for an array load or store * instruction, based on a given implied type and an observed * actual array type. * * <p>The interesting cases here have to do with object arrays, * <code>byte[]</code>s, <code>boolean[]</code>s, and * known-nulls.</p> * * <p>In the case of arrays of objects, we want to narrow the type * to the actual array present on the stack, as long as what is * present is an object type. Similarly, due to a quirk of the * original bytecode representation, the instructions for dealing * with <code>byte[]</code> and <code>boolean[]</code> are * undifferentiated, and we aim here to return whichever one was * actually present on the stack.</p> * * <p>In the case where there is a known-null on the stack where * an array is expected, our behavior depends on the implied type * of the instruction. When the implied type is a reference, we * don't attempt to infer anything, as we don't know the dimension * of the null constant and thus any explicit inferred type could * be wrong. When the implied type is a primitive, we fall back to * the implied type of the instruction. Due to the quirk described * above, this means that source code that uses * <code>boolean[]</code> might get translated surprisingly -- but * correctly -- into an instruction that specifies a * <code>byte[]</code>. It will be correct, because should the * code actually execute, it will necessarily throw a * <code>NullPointerException</code>, and it won't matter what * opcode variant is used to achieve that result.</p> * * @param impliedType {@code non-null;} type implied by the * instruction; is <i>not</i> an array type * @param foundArrayType {@code non-null;} type found on the * stack; is either an array type or a known-null * @return {@code non-null;} the array type that should be * required in this context */ private static Type requiredArrayTypeFor(Type impliedType, Type foundArrayType) { if (foundArrayType == Type.KNOWN_NULL) { return impliedType.isReference() ? Type.KNOWN_NULL : impliedType.getArrayType(); } if ((impliedType == Type.OBJECT) && foundArrayType.isArray() && foundArrayType.getComponentType().isReference()) { return foundArrayType; } if ((impliedType == Type.BYTE) && (foundArrayType == Type.BOOLEAN_ARRAY)) { /* * Per above, an instruction with implied byte[] is also * allowed to be used on boolean[]. */ return Type.BOOLEAN_ARRAY; } return impliedType.getArrayType(); }
Example 6
Source File: Merger.java From J2ME-Loader with Apache License 2.0 | 4 votes |
/** * Merges two frame types. * * @param ft1 {@code non-null;} a frame type * @param ft2 {@code non-null;} another frame type * @return {@code non-null;} the result of merging the two types */ public static TypeBearer mergeType(TypeBearer ft1, TypeBearer ft2) { if ((ft1 == null) || ft1.equals(ft2)) { return ft1; } else if (ft2 == null) { return null; } else { Type type1 = ft1.getType(); Type type2 = ft2.getType(); if (type1 == type2) { return type1; } else if (type1.isReference() && type2.isReference()) { if (type1 == Type.KNOWN_NULL) { /* * A known-null merges with any other reference type to * be that reference type. */ return type2; } else if (type2 == Type.KNOWN_NULL) { /* * The same as above, but this time it's type2 that's * the known-null. */ return type1; } else if (type1.isArray() && type2.isArray()) { TypeBearer componentUnion = mergeType(type1.getComponentType(), type2.getComponentType()); if (componentUnion == null) { /* * At least one of the types is a primitive type, * so the merged result is just Object. */ return Type.OBJECT; } return ((Type) componentUnion).getArrayType(); } else { /* * All other unequal reference types get merged to be * Object in this phase. This is fine here, but it * won't be the right thing to do in the verifier. */ return Type.OBJECT; } } else if (type1.isIntlike() && type2.isIntlike()) { /* * Merging two non-identical int-like types results in * the type int. */ return Type.INT; } else { return null; } } }
Example 7
Source File: Simulator.java From buck with Apache License 2.0 | 4 votes |
/** * Returns the required array type for an array load or store * instruction, based on a given implied type and an observed * actual array type. * * <p>The interesting cases here have to do with object arrays, * <code>byte[]</code>s, <code>boolean[]</code>s, and * known-nulls.</p> * * <p>In the case of arrays of objects, we want to narrow the type * to the actual array present on the stack, as long as what is * present is an object type. Similarly, due to a quirk of the * original bytecode representation, the instructions for dealing * with <code>byte[]</code> and <code>boolean[]</code> are * undifferentiated, and we aim here to return whichever one was * actually present on the stack.</p> * * <p>In the case where there is a known-null on the stack where * an array is expected, our behavior depends on the implied type * of the instruction. When the implied type is a reference, we * don't attempt to infer anything, as we don't know the dimension * of the null constant and thus any explicit inferred type could * be wrong. When the implied type is a primitive, we fall back to * the implied type of the instruction. Due to the quirk described * above, this means that source code that uses * <code>boolean[]</code> might get translated surprisingly -- but * correctly -- into an instruction that specifies a * <code>byte[]</code>. It will be correct, because should the * code actually execute, it will necessarily throw a * <code>NullPointerException</code>, and it won't matter what * opcode variant is used to achieve that result.</p> * * @param impliedType {@code non-null;} type implied by the * instruction; is <i>not</i> an array type * @param foundArrayType {@code non-null;} type found on the * stack; is either an array type or a known-null * @return {@code non-null;} the array type that should be * required in this context */ private static Type requiredArrayTypeFor(Type impliedType, Type foundArrayType) { if (foundArrayType == Type.KNOWN_NULL) { return impliedType.isReference() ? Type.KNOWN_NULL : impliedType.getArrayType(); } if ((impliedType == Type.OBJECT) && foundArrayType.isArray() && foundArrayType.getComponentType().isReference()) { return foundArrayType; } if ((impliedType == Type.BYTE) && (foundArrayType == Type.BOOLEAN_ARRAY)) { /* * Per above, an instruction with implied byte[] is also * allowed to be used on boolean[]. */ return Type.BOOLEAN_ARRAY; } return impliedType.getArrayType(); }
Example 8
Source File: Merger.java From buck with Apache License 2.0 | 4 votes |
/** * Merges two frame types. * * @param ft1 {@code non-null;} a frame type * @param ft2 {@code non-null;} another frame type * @return {@code non-null;} the result of merging the two types */ public static TypeBearer mergeType(TypeBearer ft1, TypeBearer ft2) { if ((ft1 == null) || ft1.equals(ft2)) { return ft1; } else if (ft2 == null) { return null; } else { Type type1 = ft1.getType(); Type type2 = ft2.getType(); if (type1 == type2) { return type1; } else if (type1.isReference() && type2.isReference()) { if (type1 == Type.KNOWN_NULL) { /* * A known-null merges with any other reference type to * be that reference type. */ return type2; } else if (type2 == Type.KNOWN_NULL) { /* * The same as above, but this time it's type2 that's * the known-null. */ return type1; } else if (type1.isArray() && type2.isArray()) { TypeBearer componentUnion = mergeType(type1.getComponentType(), type2.getComponentType()); if (componentUnion == null) { /* * At least one of the types is a primitive type, * so the merged result is just Object. */ return Type.OBJECT; } return ((Type) componentUnion).getArrayType(); } else { /* * All other unequal reference types get merged to be * Object in this phase. This is fine here, but it * won't be the right thing to do in the verifier. */ return Type.OBJECT; } } else if (type1.isIntlike() && type2.isIntlike()) { /* * Merging two non-identical int-like types results in * the type int. */ return Type.INT; } else { return null; } } }