Java Code Examples for com.google.common.primitives.Longs#BYTES
The following examples show how to use
com.google.common.primitives.Longs#BYTES .
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Example 1
Source File: Bucket.java From attic-apex-malhar with Apache License 2.0 | 5 votes |
public long getSize() { long size = 0; if (value != null) { size += value.length; } size += Longs.BYTES; //time-bucket return size; }
Example 2
Source File: MetricUtils.java From jstorm with Apache License 2.0 | 5 votes |
public static byte[] longs2bytes(long[] points) { int len = points.length; byte[] bytePts = new byte[len * Longs.BYTES]; for (int i = 0; i < len; i++) { Bytes.putLong(bytePts, i * Longs.BYTES, points[i]); } return bytePts; }
Example 3
Source File: Utils.java From bitherj with Apache License 2.0 | 5 votes |
public static long parseLongFromAddress(InetAddress address) { byte[] bytes = address.getAddress(); if (bytes.length >= Longs.BYTES) { return Longs.fromByteArray(bytes); } else { return Ints.fromByteArray(bytes); } }
Example 4
Source File: ResultSetUtil.java From shardingsphere with Apache License 2.0 | 5 votes |
private static Object convertByteArrayValue(final Object value, final Class<?> convertType) { byte[] bytesValue = (byte[]) value; switch (bytesValue.length) { case 1: return convertNumberValue(bytesValue[0], convertType); case Shorts.BYTES: return convertNumberValue(Shorts.fromByteArray(bytesValue), convertType); case Ints.BYTES: return convertNumberValue(Ints.fromByteArray(bytesValue), convertType); case Longs.BYTES: return convertNumberValue(Longs.fromByteArray(bytesValue), convertType); default: return value; } }
Example 5
Source File: BestEffortLongFile.java From big-c with Apache License 2.0 | 5 votes |
private void lazyOpen() throws IOException { if (ch != null) { return; } // Load current value. byte[] data = null; try { data = Files.toByteArray(file); } catch (FileNotFoundException fnfe) { // Expected - this will use default value. } if (data != null && data.length != 0) { if (data.length != Longs.BYTES) { throw new IOException("File " + file + " had invalid length: " + data.length); } value = Longs.fromByteArray(data); } else { value = defaultVal; } // Now open file for future writes. RandomAccessFile raf = new RandomAccessFile(file, "rw"); try { ch = raf.getChannel(); } finally { if (ch == null) { IOUtils.closeStream(raf); } } }
Example 6
Source File: FastByteOperations.java From dble with GNU General Public License v2.0 | 5 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand: a byte[] or null * @param buffer2 right operand: a byte[] or null * @param memoryOffset1 Where to start comparing in the left buffer (pure memory address if buffer1 is null, or relative otherwise) * @param memoryOffset2 Where to start comparing in the right buffer (pure memory address if buffer1 is null, or relative otherwise) * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ public static int compareTo(Object buffer1, long memoryOffset1, int length1, Object buffer2, long memoryOffset2, int length2) { int minLength = Math.min(length1, length2); /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ int wordComparisons = minLength & ~7; for (int i = 0; i < wordComparisons; i += Longs.BYTES) { long lw = THE_UNSAFE.getLong(buffer1, memoryOffset1 + (long) i); long rw = THE_UNSAFE.getLong(buffer2, memoryOffset2 + (long) i); if (lw != rw) { if (BIG_ENDIAN) { return UnsignedLongs.compare(lw, rw); } return UnsignedLongs.compare(Long.reverseBytes(lw), Long.reverseBytes(rw)); } } for (int i = wordComparisons; i < minLength; i++) { int b1 = THE_UNSAFE.getByte(buffer1, memoryOffset1 + i) & 0xFF; int b2 = THE_UNSAFE.getByte(buffer2, memoryOffset2 + i) & 0xFF; if (b1 != b2) { return b1 - b2; } } return length1 - length2; }
Example 7
Source File: BestEffortLongFile.java From hadoop with Apache License 2.0 | 5 votes |
private void lazyOpen() throws IOException { if (ch != null) { return; } // Load current value. byte[] data = null; try { data = Files.toByteArray(file); } catch (FileNotFoundException fnfe) { // Expected - this will use default value. } if (data != null && data.length != 0) { if (data.length != Longs.BYTES) { throw new IOException("File " + file + " had invalid length: " + data.length); } value = Longs.fromByteArray(data); } else { value = defaultVal; } // Now open file for future writes. RandomAccessFile raf = new RandomAccessFile(file, "rw"); try { ch = raf.getChannel(); } finally { if (ch == null) { IOUtils.closeStream(raf); } } }
Example 8
Source File: FastByteOperations.java From Mycat2 with GNU General Public License v3.0 | 5 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand: a byte[] or null * @param buffer2 right operand: a byte[] or null * @param memoryOffset1 Where to start comparing in the left buffer (pure memory address if buffer1 is null, or relative otherwise) * @param memoryOffset2 Where to start comparing in the right buffer (pure memory address if buffer1 is null, or relative otherwise) * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ public static int compareTo(Object buffer1, long memoryOffset1, int length1, Object buffer2, long memoryOffset2, int length2) { int minLength = Math.min(length1, length2); /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ int wordComparisons = minLength & ~7; for (int i = 0; i < wordComparisons ; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, memoryOffset1 + (long) i); long rw = theUnsafe.getLong(buffer2, memoryOffset2 + (long) i); if (lw != rw) { if (BIG_ENDIAN) { return UnsignedLongs.compare(lw, rw); } return UnsignedLongs.compare(Long.reverseBytes(lw), Long.reverseBytes(rw)); } } for (int i = wordComparisons ; i < minLength ; i++) { int b1 = theUnsafe.getByte(buffer1, memoryOffset1 + i) & 0xFF; int b2 = theUnsafe.getByte(buffer2, memoryOffset2 + i) & 0xFF; if (b1 != b2) { return b1 - b2; } } return length1 - length2; }
Example 9
Source File: UnsignedByteBuffer.java From tracingplane-java with BSD 3-Clause "New" or "Revised" License | 4 votes |
@Override public int compare(ByteBuffer left, ByteBuffer right) { if (!left.hasArray() || !right.hasArray()) { // TODO: might nonetheless be faster to copy bytes out of buffers in chunks of 8 return UnsignedByteBuffer.lexicographicalComparatorJavaImpl().compare(left, right); } int initialLeftPosition = left.position(); int initialRightPosition = right.position(); try { int minLength = Math.min(left.remaining(), right.remaining()); int minWords = minLength / Longs.BYTES; byte[] leftArray = left.array(); byte[] rightArray = right.array(); int leftOffset = left.arrayOffset() + initialLeftPosition; int rightOffset = right.arrayOffset() + initialRightPosition; /* Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a time is no slower than * comparing 4 bytes at a time even on 32-bit. On the other hand, it is substantially faster on * 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(leftArray, BYTE_ARRAY_BASE_OFFSET + leftOffset + (long) i); long rw = theUnsafe.getLong(rightArray, BYTE_ARRAY_BASE_OFFSET + rightOffset + (long) i); if (lw != rw) { if (BIG_ENDIAN) { return UnsignedLongs.compare(lw, rw); } /* We want to compare only the first index where left[index] != right[index]. This * corresponds to the least significant nonzero byte in lw ^ rw, since lw and rw are * little-endian. Long.numberOfTrailingZeros(diff) tells us the least significant nonzero * bit, and zeroing out the first three bits of L.nTZ gives us the shift to get that least * significant nonzero byte. */ int n = Long.numberOfTrailingZeros(lw ^ rw) & ~0x7; return ((int) ((lw >>> n) & UNSIGNED_MASK)) - ((int) ((rw >>> n) & UNSIGNED_MASK)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare(leftArray[leftOffset + i], rightArray[rightOffset + i]); if (result != 0) { return result; } } return left.remaining() - right.remaining(); } finally { left.position(initialLeftPosition); right.position(initialRightPosition); } }
Example 10
Source File: FastByteComparisons.java From hadoop with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare( buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 11
Source File: FastByteComparisons.java From big-c with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare( buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 12
Source File: FastByteComparisons.java From client-java with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo( byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare(buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 13
Source File: HadoopUtils.java From ignite with Apache License 2.0 | 4 votes |
/** * Internal comparison routine. * * @param buf1 Bytes 1. * @param len1 Length 1. * @param ptr2 Pointer 2. * @param len2 Length 2. * @return Result. */ @SuppressWarnings("SuspiciousNameCombination") public static int compareBytes(byte[] buf1, int len1, long ptr2, int len2) { int minLength = Math.min(len1, len2); int minWords = minLength / Longs.BYTES; for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = GridUnsafe.getLong(buf1, GridUnsafe.BYTE_ARR_OFF + i); long rw = GridUnsafe.getLong(ptr2 + i); long diff = lw ^ rw; if (diff != 0) { if (GridUnsafe.BIG_ENDIAN) return (lw + Long.MIN_VALUE) < (rw + Long.MIN_VALUE) ? -1 : 1; // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) n += 16; else x = y; y = x << 8; if (y == 0) n += 8; return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int res = UnsignedBytes.compare(buf1[i], GridUnsafe.getByte(ptr2 + i)); if (res != 0) return res; } return len1 - len2; }
Example 14
Source File: FastByteComparison.java From rya with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(final byte[] buffer1, final int offset1, final int length1, final byte[] buffer2, final int offset2, final int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } final int minLength = Math.min(length1, length2); final int minWords = minLength / Longs.BYTES; final int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; final int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 * bytes at a time is no slower than comparing 4 bytes at a time * even on 32-bit. On the other hand, it is substantially faster * on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { final long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); final long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); final long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) ((lw >>> n & 0xFFL) - (rw >>> n & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { final int result = UnsignedBytes.compare(buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 15
Source File: UnSafeTupleBytesComparator.java From tajo with Apache License 2.0 | 4 votes |
public static int compare(long ptr1, long ptr2) { int lstrLen = UNSAFE.getInt(ptr1); int rstrLen = UNSAFE.getInt(ptr2); ptr1 += SizeOf.SIZE_OF_INT; ptr2 += SizeOf.SIZE_OF_INT; int minLength = Math.min(lstrLen, rstrLen); int minWords = minLength / Longs.BYTES; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = UNSAFE.getLong(ptr1); long rw = UNSAFE.getLong(ptr2); if (lw != rw) { if (!littleEndian) { return UnsignedLongs.compare(lw, rw); } /* * We want to compare only the first index where left[index] != right[index]. * This corresponds to the least significant nonzero byte in lw ^ rw, since lw * and rw are little-endian. Long.numberOfTrailingZeros(diff) tells us the least * significant nonzero bit, and zeroing out the first three bits of L.nTZ gives us the * shift to get that least significant nonzero byte. */ int n = Long.numberOfTrailingZeros(lw ^ rw) & ~0x7; return (int) (((lw >>> n) & UNSIGNED_MASK) - ((rw >>> n) & UNSIGNED_MASK)); } ptr1 += SizeOf.SIZE_OF_LONG; ptr2 += SizeOf.SIZE_OF_LONG; } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare(UNSAFE.getByte(ptr1++), UNSAFE.getByte(ptr2++)); if (result != 0) { return result; } } return lstrLen - rstrLen; }
Example 16
Source File: UnsafeComparer.java From tajo with Apache License 2.0 | 4 votes |
@Override public int compare(byte[] left, byte[] right) { int minLength = Math.min(left.length, right.length); int minWords = minLength / Longs.BYTES; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(left, BYTE_ARRAY_BASE_OFFSET + (long) i); long rw = theUnsafe.getLong(right, BYTE_ARRAY_BASE_OFFSET + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return UnsignedLongs.compare(lw, rw); } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare(left[i], right[i]); if (result != 0) { return result; } } return left.length - right.length; }
Example 17
Source File: FastByteComparisons.java From tikv-client-lib-java with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare( buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 18
Source File: FastByteComparisons.java From ethereumj with MIT License | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare( buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }
Example 19
Source File: DescVarLengthFastByteComparisons.java From phoenix with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 * left operand * @param buffer2 * right operand * @param offset1 * Where to start comparing in the left buffer * @param offset2 * Where to start comparing in the right buffer * @param length1 * How much to compare from the left buffer * @param length2 * How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } if (length1 == 0 && length2 != 0) { // nulls sort first, even for descending return -1; } if (length2 == 0 && length1 != 0) { // nulls sort first, even for descending return 1; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a time is no slower than comparing * 4 bytes at a time even on 32-bit. On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long)i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long)i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int)diff; if (x == 0) { x = (int)(diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int)(((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare(buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length2 - length1; }
Example 20
Source File: FastByteComparisons.java From tez with Apache License 2.0 | 4 votes |
/** * Lexicographically compare two arrays. * * @param buffer1 left operand * @param buffer2 right operand * @param offset1 Where to start comparing in the left buffer * @param offset2 Where to start comparing in the right buffer * @param length1 How much to compare from the left buffer * @param length2 How much to compare from the right buffer * @return 0 if equal, < 0 if left is less than right, etc. */ @Override public int compareTo(byte[] buffer1, int offset1, int length1, byte[] buffer2, int offset2, int length2) { // Short circuit equal case if (buffer1 == buffer2 && offset1 == offset2 && length1 == length2) { return 0; } int minLength = Math.min(length1, length2); int minWords = minLength / Longs.BYTES; int offset1Adj = offset1 + BYTE_ARRAY_BASE_OFFSET; int offset2Adj = offset2 + BYTE_ARRAY_BASE_OFFSET; /* * Compare 8 bytes at a time. Benchmarking shows comparing 8 bytes at a * time is no slower than comparing 4 bytes at a time even on 32-bit. * On the other hand, it is substantially faster on 64-bit. */ for (int i = 0; i < minWords * Longs.BYTES; i += Longs.BYTES) { long lw = theUnsafe.getLong(buffer1, offset1Adj + (long) i); long rw = theUnsafe.getLong(buffer2, offset2Adj + (long) i); long diff = lw ^ rw; if (diff != 0) { if (!littleEndian) { return lessThanUnsigned(lw, rw) ? -1 : 1; } // Use binary search int n = 0; int y; int x = (int) diff; if (x == 0) { x = (int) (diff >>> 32); n = 32; } y = x << 16; if (y == 0) { n += 16; } else { x = y; } y = x << 8; if (y == 0) { n += 8; } return (int) (((lw >>> n) & 0xFFL) - ((rw >>> n) & 0xFFL)); } } // The epilogue to cover the last (minLength % 8) elements. for (int i = minWords * Longs.BYTES; i < minLength; i++) { int result = UnsignedBytes.compare( buffer1[offset1 + i], buffer2[offset2 + i]); if (result != 0) { return result; } } return length1 - length2; }