Java Code Examples for com.google.javascript.rhino.jstype.FunctionType#getTopMostDefiningType()
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com.google.javascript.rhino.jstype.FunctionType#getTopMostDefiningType() .
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Example 1
Source File: Closure_96_TypeCheck_t.java From coming with MIT License | 4 votes |
/** * Given a constructor type and a property name, check that the property has * the JSDoc annotation @override iff the property is declared on a * superclass. Several checks regarding inheritance correctness are also * performed. */ private void checkDeclaredPropertyInheritance( NodeTraversal t, Node n, FunctionType ctorType, String propertyName, JSDocInfo info, JSType propertyType) { // TODO(user): We're not 100% confident that type-checking works, // so we return quietly if the unknown type is a superclass of this type. // Remove this check as we become more confident. We should flag a warning // when the unknown type is on the inheritance chain, as it is likely // because of a programmer error. if (ctorType.hasUnknownSupertype()) { return; } FunctionType superClass = ctorType.getSuperClassConstructor(); boolean superClassHasProperty = superClass != null && superClass.getPrototype().hasProperty(propertyName); boolean declaredOverride = info != null && info.isOverride(); boolean foundInterfaceProperty = false; if (ctorType.isConstructor()) { for (JSType implementedInterface : ctorType.getImplementedInterfaces()) { if (implementedInterface.isUnknownType()) { continue; } FunctionType interfaceType = implementedInterface.toObjectType().getConstructor(); boolean interfaceHasProperty = interfaceType.getPrototype().hasProperty(propertyName); foundInterfaceProperty = foundInterfaceProperty || interfaceHasProperty; if (reportMissingOverride.isOn() && !declaredOverride && interfaceHasProperty) { // @override not present, but the property does override an interface // property compiler.report(t.makeError(n, reportMissingOverride, HIDDEN_INTERFACE_PROPERTY, propertyName, interfaceType.getTopMostDefiningType(propertyName).toString())); } if (!declaredOverride) { continue; } // @override is present and we have to check that it is ok if (interfaceHasProperty) { JSType interfacePropType = interfaceType.getPrototype().getPropertyType(propertyName); if (!propertyType.canAssignTo(interfacePropType)) { compiler.report(t.makeError(n, HIDDEN_INTERFACE_PROPERTY_MISMATCH, propertyName, interfaceType.getTopMostDefiningType(propertyName).toString(), interfacePropType.toString(), propertyType.toString())); } } } } if (!declaredOverride && !superClassHasProperty) { // nothing to do here, it's just a plain new property return; } JSType topInstanceType = superClassHasProperty ? superClass.getTopMostDefiningType(propertyName) : null; if (reportMissingOverride.isOn() && ctorType.isConstructor() && !declaredOverride && superClassHasProperty) { // @override not present, but the property does override a superclass // property compiler.report(t.makeError(n, reportMissingOverride, HIDDEN_SUPERCLASS_PROPERTY, propertyName, topInstanceType.toString())); } if (!declaredOverride) { // there's no @override to check return; } // @override is present and we have to check that it is ok if (superClassHasProperty) { // there is a superclass implementation JSType superClassPropType = superClass.getPrototype().getPropertyType(propertyName); if (!propertyType.canAssignTo(superClassPropType)) { compiler.report( t.makeError(n, HIDDEN_SUPERCLASS_PROPERTY_MISMATCH, propertyName, topInstanceType.toString(), superClassPropType.toString(), propertyType.toString())); } } else if (!foundInterfaceProperty) { // there is no superclass nor interface implementation compiler.report( t.makeError(n, UNKNOWN_OVERRIDE, propertyName, ctorType.getInstanceType().toString())); } }
Example 2
Source File: Closure_96_TypeCheck_s.java From coming with MIT License | 4 votes |
/** * Given a constructor type and a property name, check that the property has * the JSDoc annotation @override iff the property is declared on a * superclass. Several checks regarding inheritance correctness are also * performed. */ private void checkDeclaredPropertyInheritance( NodeTraversal t, Node n, FunctionType ctorType, String propertyName, JSDocInfo info, JSType propertyType) { // TODO(user): We're not 100% confident that type-checking works, // so we return quietly if the unknown type is a superclass of this type. // Remove this check as we become more confident. We should flag a warning // when the unknown type is on the inheritance chain, as it is likely // because of a programmer error. if (ctorType.hasUnknownSupertype()) { return; } FunctionType superClass = ctorType.getSuperClassConstructor(); boolean superClassHasProperty = superClass != null && superClass.getPrototype().hasProperty(propertyName); boolean declaredOverride = info != null && info.isOverride(); boolean foundInterfaceProperty = false; if (ctorType.isConstructor()) { for (JSType implementedInterface : ctorType.getImplementedInterfaces()) { if (implementedInterface.isUnknownType()) { continue; } FunctionType interfaceType = implementedInterface.toObjectType().getConstructor(); boolean interfaceHasProperty = interfaceType.getPrototype().hasProperty(propertyName); foundInterfaceProperty = foundInterfaceProperty || interfaceHasProperty; if (reportMissingOverride.isOn() && !declaredOverride && interfaceHasProperty) { // @override not present, but the property does override an interface // property compiler.report(t.makeError(n, reportMissingOverride, HIDDEN_INTERFACE_PROPERTY, propertyName, interfaceType.getTopMostDefiningType(propertyName).toString())); } if (!declaredOverride) { continue; } // @override is present and we have to check that it is ok if (interfaceHasProperty) { JSType interfacePropType = interfaceType.getPrototype().getPropertyType(propertyName); if (!propertyType.canAssignTo(interfacePropType)) { compiler.report(t.makeError(n, HIDDEN_INTERFACE_PROPERTY_MISMATCH, propertyName, interfaceType.getTopMostDefiningType(propertyName).toString(), interfacePropType.toString(), propertyType.toString())); } } } } if (!declaredOverride && !superClassHasProperty) { // nothing to do here, it's just a plain new property return; } JSType topInstanceType = superClassHasProperty ? superClass.getTopMostDefiningType(propertyName) : null; if (reportMissingOverride.isOn() && ctorType.isConstructor() && !declaredOverride && superClassHasProperty) { // @override not present, but the property does override a superclass // property compiler.report(t.makeError(n, reportMissingOverride, HIDDEN_SUPERCLASS_PROPERTY, propertyName, topInstanceType.toString())); } if (!declaredOverride) { // there's no @override to check return; } // @override is present and we have to check that it is ok if (superClassHasProperty) { // there is a superclass implementation JSType superClassPropType = superClass.getPrototype().getPropertyType(propertyName); if (!propertyType.canAssignTo(superClassPropType)) { compiler.report( t.makeError(n, HIDDEN_SUPERCLASS_PROPERTY_MISMATCH, propertyName, topInstanceType.toString(), superClassPropType.toString(), propertyType.toString())); } } else if (!foundInterfaceProperty) { // there is no superclass nor interface implementation compiler.report( t.makeError(n, UNKNOWN_OVERRIDE, propertyName, ctorType.getInstanceType().toString())); } }