ramda#sortWith TypeScript Examples
The following examples show how to use
ramda#sortWith.
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Example #1
Source File: utils.ts From reskript with MIT License | 7 votes |
drawAssetReport = (assets: Asset[]) => {
const toTemplateData = (asset: Asset) => {
const config = getExtensionConfig(path.extname(asset.name));
return {
name: asset.name,
color: config.color,
typeOrder: config.order,
size: (asset.size / 1024).toFixed(2) + 'KB',
sizeInBytes: asset.size,
indicator: asset.initial ? 'initial' : '',
};
};
const templateSegments = sortWith(
[
ascend(data => data.typeOrder),
ascend(data => (data.indicator === 'initial' ? 0 : 1)),
ascend(asset => asset.name),
],
uniqBy(v => v.name, assets).map(toTemplateData)
);
const maxNameLength = templateSegments.map(segment => segment.name.length).reduce((x, y) => Math.max(x, y), 0);
const maxSizeLength = templateSegments.map(segment => segment.size.length).reduce((x, y) => Math.max(x, y), 0);
for (const {color, name, size, indicator} of templateSegments) {
logger.log(kolorist[color](`${name.padStart(maxNameLength)} ${size.padEnd(maxSizeLength)} ${indicator}`));
}
}
Example #2
Source File: useNextQuestion.tsx From nosgestesclimat-site with MIT License | 6 votes |
export function getNextSteps(
missingVariables: Array<MissingVariables>
): Array<DottedName> {
const byCount = ([, [count]]: [unknown, [number]]) => count
const byScore = ([, [, score]]: [unknown, [unknown, number]]) => score
const missingByTotalScore = reduce<MissingVariables, MissingVariables>(
mergeWith(add),
{},
missingVariables
)
const innerKeys = flatten(map(keys, missingVariables)),
missingByTargetsAdvanced = Object.fromEntries(
Object.entries(countBy(identity, innerKeys)).map(
// Give higher score to top level questions
([name, score]) => [
name,
score + Math.max(0, 4 - name.split('.').length),
]
)
)
const missingByCompound = mergeWith(
pair,
missingByTargetsAdvanced,
missingByTotalScore
),
pairs = toPairs<number>(missingByCompound),
sortedPairs = sortWith([descend(byCount), descend(byScore) as any], pairs)
return map(head, sortedPairs) as any
}